tentukan penyelesaiannya tolong ya kak
Jawab:
[tex]\sqrt[3]{\frac{1}{4^{12\times3x}} } =\frac{1}{8^{x-1}}[/tex]
[tex]\sqrt[3]{\frac{1}{2^{2(36x)}} } =\frac{1}{2^{3(x-1)}}[/tex]
[tex]\sqrt[3]{2^{-72x}} =2^{-3(x-1)[/tex]
[tex]2^{\frac{-72x}{3}} =2^{-3(x-1)[/tex]
[tex]\frac{-72x}{3}=-3(x-1)[/tex]
-24x = -3(x-1)
8x = x - 1
7x = -1
[tex]x=-\frac{1}{7}[/tex]
semohga bermanfaaat..........
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